Electronegativity values of elements x and y are3.8 and 1.8 respectively ionic percentage of compound
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Answer:
% of I.C = 46%
Explanation:
Ionic percentage is calculated by the formula used below:
%of I.C= 16(x-y) + 3.5(x-y)^2
=> 16(3.8-1.8) + 3.5(3.8-1.8)^2
=> 16(2.0) + 3.5(2.0)^2
=> 32 + 3.5*4
=> 32+14
=> 46%
Therefore IONIC % of compound= 46%
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