Question

electronic configuration an element is 1s2 2s2 2p6 3s2 3p1 and mass no is 27 Mention the no of fundamental particles present in it and write its position​

Answer 1

Answer:

Electronic configuration = 1s2 2s2 2p6 3s2 3p1.

The element has 13 electrons.

13 protons.

14 neutrons.

Atomic mass = no of protons and no of neutrons

=13+14

=27

And the element is Aluminum.

It is present in 13 th group and 3 rd period in periodic table or it is present in boron family.

Answer 2

Answer:

REPRESENTATIVE ELEMENT

Step-by-step explanation:

As last electron is filled in 3p−orbital so it belongs to the p-block. S-block and p-block elements are representative elements