Science, asked by atharvakangali28, 1 month ago

Electronic configuration Na is 1s² 2s² 2p⁶ 3s¹. To which period and group will it belong respectively?

Answers

Answered by ridhya77677

3

Answer:

Na(11) => 1s² 2s² 2p⁶ 3s¹

The last electron is in s block and 3rd shell. The unpaired electron is 1.

So, period = 3

group = 1

block => s

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