Question

electronic configuration of four elements are given on the table arrange this element in the increasing order of the electron egatively

give reason​

Answer 1

Answer:

c < n < o < f is the order of electronegitivity

Answer 2

The order of increasing electro-negativity is

C < N < O < F

Explanation:

• The four elements mentioned in the table are carbon , Nitrogen , Oxygen and Fluorine.
• The atomic number of carbon is 6 and it electronic configuration
• C = 1s^2, 2s^2, 2p^2
• Atomic number of nitrogen is 7 and its electronic configuration:
• N = 1s^2, 2s^2, 2p^3
• Atomic number of oxygen is 8 and its electronic configuration:
• O =  1s^2, 2s^2, 2p^4
• Atomic number of Fluorine is 9 and its electronic configuration:
• F =  1s^2, 2s^2, 2p^5
• The order of increasing electro-negativity is
• C < N < O < F

Hence Fluorine is the most electro-negative element.