Question

electronic configuration of sodium is 1s2 2S2 2p6 3s1 then write the four quantum number of the first electronic k shell​

Answer 1

Answer:

Na - 1s2/ 2s2 2p6/3s1

k- 1s2/2s2 2p6/3s2 3p6/ 4s1

Answer 2

Given: Electronic configuration of sodium is 1s2 2S2 2p6 3s1.

To find: We have to find its quantum numbers.

Solution:

The electronic configuration of the Na atom is 1s2 2S2 2p6 3s1.

Thus its valance shell is 3s and principal quantum number n=3.

Azimuthal quantum number l is given as (n-1).

Thus l=3-1

l=2

Again magnetic quantum number ml will be from +l to -l.

Thus ml=+2,+1,0,-1, -2

Its valance shell have one electron thus spin quantum number will be-

$s = \frac{ + 1}{2} \\ - \frac{1}{2}$