Question

electronic configuration of the following with representation of arrangement of electrons:
{both ground as well as excited state}
1. boron
2. carbon
3. nitrogen
4. oxygen
5. fluorine

Answer 1

electronic configuration of
(i)boron 
 GS:1s² 2s² 2p¹
1st ES:1s² 2s¹ 2p²
(ii)carbon
 GS:1s² 2s² 2p²
1st ES:1s² 2s¹ 2p³
(iii)nitrogen
  GS:1s² 2s² 2p³
(iv)oxygen
  GS:1s² 2s² 2p⁴
(v) fluorine
  GS:1s² 2s² 2p⁵

nitrogen , oxygen and fluorine do not have excited state as they cannot have more than two orbitals.