Question

Electronic distribution of aluminum and neon

Answer 1

In order to write the Aluminium electron configuration we first need to know the number of electrons for the Al atom (there are 13 electrons). When we write the configuration we'll put all 13 electrons in orbitals around the nucleus of the Aluminium atom.

In writing the electron configuration for Aluminium the first two electrons will go in the 1s orbital. Since 1s can only hold two electrons the next 2 electrons for aluminium go in the 2s orbital. The nex six electrons will go in the 2p orbital. The p orbital can hold up to six electrons. We'll put six in the 2p orbital and then put the next two electrons in the 3s. Since the 3s if now full we'll move to the 3p where we'll place the remaining electron. Therefore the Aluminium electron configuration will be 1s22s22p63s23p1.

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Answer 2

Answer :

ALUMINIUM : The p orbital can hold up to six electrons. We'll put six in the 2p orbital and then put the next two electrons in the 3s. Since the 3s if now full we'll move to the 3p where we'll place the remaining electron. Therefore the Aluminium electron configuration will be 1s22s22p63s23p1.

NEON : Neon is the tenth element with a total of 10 electrons. In writing the electron configuration for neon the first two electrons will go in the 1s orbital. ... Therefore the Ne electron configuration will be 1s22s22p6. Because the second energy level (2s22p6) has eight electrons Neon has an octet and has a full outer shell.