Chemistry, asked by Anonymous, 9 months ago

Electrons are emitted with zero velocity from a metal surface when it is exposed to radiation of wavelength 6800 Å. Calculate threshold frequency (v.) and work function (W) of the metal.​

Answers

Answered by shannelle33
4

I hope it helps you....... ...... ........ ...

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Answered by BendingReality
16

Answer:

2.92 × 10⁻¹⁹ J

Explanation:

We have given :

Threshold wavelength λ₀ = 6800 Â

λ₀ in term of m :

= >  λ₀ = 6800 × 10⁻¹⁰ m

We know :

λ = c / v

= >  c =  v λ

= >  v₀ = c /  λ₀

Putting values here we get :

= >  v₀ = 3 × 10⁸ / 6800 × 10⁻¹⁰ sec⁻¹

= >  v₀ = 3 × 10⁸ / 68 × 10⁻⁸ sec⁻¹

= >  v₀ =  4.41 × 10¹⁴ sec⁻¹

Now we also know :

Work done W₀ = h v₀ :

= > W₀ = ( 6.626 × 10⁻³⁴ × 4.41 × 10¹⁴  ) J

= > W₀ = ( 6.626 × 4.41 × 10⁻²⁰ ) J

= > W₀ = 2.92 × 10⁻¹⁹ J

Hence we get required answer.

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