Physics, asked by yashrathore4804, 11 months ago

Electronsare emittedwith zero velocity from a metal surface when it is exposed toto radiation of wavelength 6000 acalculate threshold frequency and workfunction

Answers

Answered by Anonymous
0

Given λ = 6800 amgstrom or 6800x 10-10 m = 6.8 x 10-7m

C = 3 x 108 m/s

Also λ = c/v or v = c/ λ Therefore putting the values in the equation, we get

=3 x 108 / 6.8 x 10-7m = 4.41 x 1014 s-1

Hence, work function (W0) of the metal = hν0

= (6.626 × 10–34 Js) (4.41 × 1014 s–1)

= 2.922 × 10–19 J

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