Question

Electrostatic force between two charges placed in free space is F . If the charges are placed at the same separation in a medium of dielectric constant 5 the force between them Will be?

Answer 1

Answer:

when charges kept in a medium with same separation then force decrease k times of force when charges kept in air/vaccume

F=1/4π€ •q1q2/r² ....(1)

F'= 1/4π€k• q1q2/ r² .....(2)

(1)/(2)

F=F'/k

where F' is force between charges kept in air

so, F'= F/5