Question

Electrovalency of Al in AlF3

Answer 1

Answer:

Al has atomic number 13=2.8.3 so it has valency 3 and can form trivalent ions by losing them to fluorine atoms which is highly electronegative in nature.

Answer 2

Answer:

The electrovalency of $Al$ in $AlF_{3}$ is 3 .

Explanation:

The number of electrons an atom loses or gains in order to create an ionic bond is known as electrovalency. The number of electrons exchanged during the creation of an ion is known as its electrovalency.

Aluminum has three valence electrons, whereas fluorine has seven in each.

As a result, aluminium fluoride has the following total valence electrons:

$3+(3 \times 7)=24$

Each F atom typically contains three lone pairs, making up $3+(3 \times 7)=24$ of the total $24$. Therefore, three single bonds can be created, each with two valence electrons, using the remaining six valence electrons.

Therefore, the Electrovalency of $Al$ in AlF₃ is $3$ . By losing them to fluorine atoms, which are naturally quite electronegative, it can create trivalent ions.

To know more about "AlF₃"

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