Element A reacts with oxygen to form a compound A2O3. If 0.359 gram of A compound contains 0.128 g of oxygen. Atomic weight of A will be
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Let atomic mass of element A be =a g/mol
Again atomic mass of oxygen = 16 g/mol
So molar mass of the compound A2O3=(2a+48)g/mol
One molecule of the compound A2O3 Contains 2 atoms.
So the ratio of mass of A and A2O3 in a molecule 2a+482a
Again it is given that 0.359 grams of A reacts to give 0.559 grams of the compound. So we can write
=>2a+482a=0.5590.359
=>a+24a=559359
On solving, a=43.08
So, the correct option is B
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