Chemistry, asked by Anonymous, 10 months ago

Element ‘B’ forms ccp structure and ‘A’ occupies half of the octahedral voids, while
oxygen atoms occupy all the tetrahedral voids. The structure of bimetallic oxide is

Answers

Answered by Agastya0606
9

The structure of the bimetallic oxide is AB₂O₄.

Since B forms ccp structure, Z = 4 (⇒ B = 4)

Therefore, there are 4 octahedral voids and 8 tetrahedral voids.

Given, A occupies half of the octahedral voids. Therefore, A = 2

and, Oxygen atoms occupy all the tetrahedral voids. ⇒ Number of oxygen atoms = 8

A: B: O = 2:4:8 = 1: 2: 4

The structure of the compound is AB₂O₄.

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