Element ‘B’ forms ccp structure and ‘A’ occupies half of the octahedral voids, while
oxygen atoms occupy all the tetrahedral voids. The structure of bimetallic oxide is
Answers
Answered by
9
The structure of the bimetallic oxide is AB₂O₄.
Since B forms ccp structure, Z = 4 (⇒ B = 4)
Therefore, there are 4 octahedral voids and 8 tetrahedral voids.
Given, A occupies half of the octahedral voids. Therefore, A = 2
and, Oxygen atoms occupy all the tetrahedral voids. ⇒ Number of oxygen atoms = 8
A: B: O = 2:4:8 = 1: 2: 4
The structure of the compound is AB₂O₄.
Similar questions