element L has an electronic configuration of 2.8.3 and element M has a configuration of 2.6, what would be the formula of the compound formed between L and
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Answer:
The answer is AlO[Aluminium(II) Oxide]
Explanation:
Element L has electronic configuration of 2,8,3 that is it has 13 electrons. And aluminium has 13 electrons. On the other hand M has a configuration of 2,6 meaning it has a total of 8 electrons. Meaning it is oxygen. Now if you we make compound with them then it will interchange valency. Here the aluminium will be Aluminium II. So the 2 will get cut and it will result in AlO[Aluminium (II) oxide].
Hope it helps =)
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