Element X has electronic configuration 2, 8, 18, 8, 1.
Without identifying X,
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Electronic configuration of X = 2,8,18,8,1
Atomic number = 37
So element is Rubidium
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I believe your question is: The element X has the electronic configuration 2, 8, 18, 8, 1. Without identifying x,
a)predict the sign and charge on a single ion or X.
b)write if X be an oxidizing agent or reducing agent and why.
Answer:
a)X has one electron in its valence shell and to achieve a full octet, X loses an electron to form a cation. The ion has a positive sign and charge of +1.
b)Element X loses an electron and is an electropositive element and thus is oxidised in a redox reaction. So, it acts as a reducing agent.
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