Element X has electronic configuration 2,8,18,8,1. Without identifying X :
(a) predict the sign and charge on a simple ion of X.
(b) Write if X will be an oxidising or reducing agent.
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(a) The simple ion of X will be a cation with 1 unit positive charge, i.e., X⁺.
- This is due to the fact that there is only 1 electron present in its valence shell.
- So it can easily donate it.
- It can be denoted as follows :
X ------> X⁺ + e⁻
(b) X will be a reducing agent as it is capable of donating the only valence electron present in it.
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A. The sign of the charge of the ion of x will be X¹+ , the charge is positive charge
Explanation:
- B. The compound which is given above it has only one electron in addition to the inert gas configuration from stock as a result of this it has the capability to lose that one electron. As a result of this it will lose that one electron and become oxidized.
- Since oxidation and reduction reaction takes place simultaneously hence there will be reduction of the other compound ,so it is a reducing agent.
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