Question

Elemental analysis of a nitrogen oxide shows that it contains 2.8 g nitrogen and 8.0g of oxygen. The empirical formula of this oxide is

Answer 1

Hi there,

♤ Given

● N sample mass = 2.8

● N atomic mass = 14

● O sample mass= 8.0

● O atomic mass = 16

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☆ Calculate number of moles for each element by dividing sample mass over atomic mass

● n(N) = 2.8÷14 = 0.2

● n(O) = 8÷16 = 0.5

☆ Calculate mole ratio by dividing both mols over the lowest value

● N ratio is 1

● O ratio is 2.5

☆ Correction the fraction by multiple both ratios × 2

● N= 2

● O= 5

☆ The empirical formula

《 N2O5 》

♡ Hope the answer is helpful

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