Question

Elements A and B form two compounds B2A3 and
B2A. 0.05 moles of B2A3 weight 9.0 gms and
0.10 mole of B2A weight 10 gms atomic weight of
A and B are-
(A) 20 and 30 (B) 30 and 40
(C) 40 and 30 (D) 30 and 20​

Answer 1

Answer:

Explanation:

0.05 moles has 9 gm 0f B2A3

so 1 mole has 180 gm of B2A3

0.10 MOLE has 10 gm of B2A

So 1 mole has 100 gm of B2A

SO 2B+3A=180

2B+A=100

By sovling this equation we get

A=40 and B=30