Physics, asked by indhudhanu, 4 months ago

Elements A, B, C and D have 3, 20, 13 and 16 electrons respectively in their atom. Which of these is
most likely to be unable to form cation?

Answers

Answered by uzmaahmed246
1

Answer:

D. as an element having at no 16 will prefer gaining eletrons than donating ,so will form anion rather than cation

Answered by akruthika030660
0

answer is D

Explanation:

A=3 electrons.

electronic configuration is 2,1(metal)

B=20 elections

EC=2,8,8,2(metal)

C=13 electrons

EC=2,8,3(metal)

D=16 electrons.

EC=2,8,6(non metal)

metals =positively charged

non metals =negatively charged

D is a non metal so it cannot form a cation

if an element gain electrons it will form anion

if an element loses electrons it will form cation

so metals will form cation and non metals will form anion

if the number of electrons in the valence shell is less than 4 it is a metal

if the number of electrons in the valence shell is more than 4 it is a non metal

hope it helps you.

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