Chemistry, asked by mullickrahamat16, 20 days ago

Elements X and Y have octet configuration in their L shell after forming stable dipositive and dinegative ions respectively. The respective electronic configuration of the succeeding element of X and the preceding element of Y are

A. 2, 7 and 2,5
B. 2, 8, 3 and 2. 5
C. 2, 5 and 2, 8, 3
D. 2, 8, 1 and 2, 7 ​

Answers

Answered by sakshimane92561
0

Answer:

Let the dipositive ion be

Let the dipositive ion beX^(+2)

Let the dipositive ion beX^(+2)and dinegative ion is

Let the dipositive ion beX^(+2)and dinegative ion isY^(-2)

Let the dipositive ion beX^(+2)and dinegative ion isY^(-2). <br> The octet in the second shell

Let the dipositive ion beX^(+2)and dinegative ion isY^(-2). <br> The octet in the second shellto 2,8

Let the dipositive ion beX^(+2)and dinegative ion isY^(-2). <br> The octet in the second shellto 2,8<br> The number of electrons in

Let the dipositive ion beX^(+2)and dinegative ion isY^(-2). <br> The octet in the second shellto 2,8<br> The number of electrons inX=10+2=12

Let the dipositive ion beX^(+2)and dinegative ion isY^(-2). <br> The octet in the second shellto 2,8<br> The number of electrons inX=10+2=12<br> The number of electrons in

Let the dipositive ion beX^(+2)and dinegative ion isY^(-2). <br> The octet in the second shellto 2,8<br> The number of electrons inX=10+2=12<br> The number of electrons inY=10-2=8

Let the dipositive ion beX^(+2)and dinegative ion isY^(-2). <br> The octet in the second shellto 2,8<br> The number of electrons inX=10+2=12<br> The number of electrons inY=10-2=8<br> X is magneshium with an electronic configuration 2, 8,2,Y is oxygen with a congfiguration 2,6. <br> The element preceding magnesium is sodium and the succeeding one is aluminium. They have eletronic configuration

Let the dipositive ion beX^(+2)and dinegative ion isY^(-2). <br> The octet in the second shellto 2,8<br> The number of electrons inX=10+2=12<br> The number of electrons inY=10-2=8<br> X is magneshium with an electronic configuration 2, 8,2,Y is oxygen with a congfiguration 2,6. <br> The element preceding magnesium is sodium and the succeeding one is aluminium. They have eletronic configuration2,8,1, and 2,8,3

Let the dipositive ion beX^(+2)and dinegative ion isY^(-2). <br> The octet in the second shellto 2,8<br> The number of electrons inX=10+2=12<br> The number of electrons inY=10-2=8<br> X is magneshium with an electronic configuration 2, 8,2,Y is oxygen with a congfiguration 2,6. <br> The element preceding magnesium is sodium and the succeeding one is aluminium. They have eletronic configuration2,8,1, and 2,8,3, respectively. The elements preceding and succeeding for oxygen are nitrogen and fluorine which have electronic configuration 2,5 and 2,7, respectively.

Similar questions