Elements X, Y and Z have atomic number 6, 9 and 12 respectively which one:
(i) forms anion.
(ii) firms cation.
(iii) has four electrons in it's valence shells?
(iv) Type of bond formed between X and Z? give its molecular formula.
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Answer:
Explanation:
(i) element Y having atomic no.9 has 2,7 configuration.
So , they have a great tendency to accept one e- and form anion
(ii) element Z having atomic no.12 have
2,8,2 configuration. So they have high tendency to lose e- and to form cation
(iii) element X having atomic number 12 has configuration 2,4.so,it has 4e- in valence shell.
(IV) element Z is metal and element Y is
Non-metal.
(v) ionic
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