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Using division, show that (x-1) is a factor of (x-1).
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To check whether (x−1) is factor of x
10
−1 and x
11
−1
Then value of p(x)=x
10
−1 and q(x)=x
11
−1 is zero when x−1=0 or x=1
Replace x by 1 we get
p(x)=x
10
−1
p(1)=(1)
10
−1
p(1)=1−1=0
and q(x)=x
11
−1
q(1)=(1)
11
−1
q(1)=1−1=0
So p(1) and q(1) are zero
then x−1 is a factor of x
10
−1 and x
11
−1
Answered By
toppr
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