Question

elevator descends into a mine shaft at the rate of 6 metre per minute if the recent start from 10 in above the ground level how long it will take to reach 350 metres​

Answer 1

From the question,

The initial height of the elevator = 10 m

Final depth of elevator = - 350 m … [∵distance descended is denoted by a negative

integer]

The total distance to descended by the elevator = (-350) – (10)

= - 360 m

Then,

Time taken by the elevator to descend -6 m = 1 min

So, time taken by the elevator to descend – 360 m = (-360) ÷ (-60)

= 60 minutes

= 1 hour

Answer 2

distance =350 +10=360

time=distance\speed

=360\6

=60 minute (answer)