Question

elevator descends into a mine shalf at the rate 6m/min . if the desent starts from 10 metre above the ground level how long will it take to reach - 350​

Answer 1

Answer:

Starting point=10 m

Ending point =-350m

Total distance=(10 +350) m = 360m

Speed=6m/min

Time =d/t=(360÷6)min=60 min

answer=1 hour

Answer 2

Answer:

60Minutes

Step-by-step explanation:

a=6m/min

u=0

s=360

t=?

$\frac{v - u}{a } = t$

$\frac{6 - 0}{6 } = \frac{6}{6 } = 1hours$

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