elevator to desends into a mine shaft at the rate of 5 M per minute .what will be its position after 1 hour? if it begins to desends from 15 M above the ground, what will be its position after 45 minutes?
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1. Distance it descends per minute = 5m
Hence, distance it descends in 60minutes
= 5 x 60 =300m.
Thus after one hour, its position is 300m below sea level.
2. Again, distance is descends per minute
= 5m
So distance it covers in 45minutes = 5 x 45
= 225m
But its given that it has already covered a distance of 15m.
So Total distance below ground =
15 +225 = 240m
Thus in second case, its 240m below sea level.
Hence, distance it descends in 60minutes
= 5 x 60 =300m.
Thus after one hour, its position is 300m below sea level.
2. Again, distance is descends per minute
= 5m
So distance it covers in 45minutes = 5 x 45
= 225m
But its given that it has already covered a distance of 15m.
So Total distance below ground =
15 +225 = 240m
Thus in second case, its 240m below sea level.
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