Question

Eleven bags of wheat flour, each marked 5 kg, actually contained the following

weights of flour (in kg): 4.97, 5.05, 5.08, 5.03, 5.00, 5.06, 5.08, 4.98, 5.04,

5.07, 5.00

Find the probability that any of these bags chosen at random contains more than 5

kg of flour.​

Answer 1

Answer:

Given bag of wheat flour are 

4.97,5.05,5.05,5.03,5.00,5.06,5.08,4.98,5.04,5.07,5.00

The total number of wheat flour bags =11.

The number of wheat flour bags contain more than 5 Kg are 7.

Then probability of bags chosen at random =   number of bags more than 5 kg

Given bag of wheat flour are 

4.97,5.05,5.05,5.03,5.00,5.06,5.08,4.98,5.04,5.07,5.00

The total number of wheat flour bags =11.

The number of wheat flour bags contain more than 5 Kg are 7.

Then probability of bags chosen at random =  

number of bags more than 5 kg

total number of bags =7/11

Step-by-step explanation:

Then answer is the 7/11