Question

Eliminate θ from x= 4 secθ , y= 5 tan θ

Answer 1

Step-by-step explanation:

$x = 4 \: sec \theta \: \implies \: sec \theta = \frac{x}{4} \\ y = 5 \: tan \theta \: \implies \: tan \theta = \frac{y}{5} \\ \because \: {sec}^{2} \theta - {tan}^{2} \theta = 1 \\ \therefore \: ( { \frac{x}{4} })^{2} - ( { \frac{y}{5} })^{2} = 1 \\ \frac{ {x}^{2} }{16} - \frac{ {y}^{2} }{25} = 1$

Answer 2

Answer:

Step-by-step explanation:Answer:87.5%

Step-by-step explanation:

increase in size =3.5

percentage of increment=

(3.5÷4)×100=0.875×100=87.5