eliminate theta from the following x=7+3cos theta, y=5+3sin theta Plz give me ans.
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Step-by-step explanation:
x=7+3cosθ ----(1)
y=5+3sinθ ----(2)
by solving equation (1)
cosθ= (x-7)/3
square on both side:
cos^2θ= (x-7)^2/(3)^2
cos^2θ= (x^2 -14x +49)/9 ----(3)
by solving equation (2)
sinθ=(y-5)/3
square on both side:
sin^2θ=(y-5)^2/(3)^2
sin^2θ=(y^2 -10y +25)/9 ------(4)
adding equation (3) &(4)
sin^2θ+cos^2θ=(y^2 -10y +25)/9 + (x^2 -14x +49)/9
As we, sin^2θ+cos^2θ =1
so, 1 = (y^2 -10y +25)/9 + (x^2 -14x +49)/9
1 = 1/9[(y^2 -10y +25) + (x^2 -14x +49)]
9 = [y^2 -10y +25 + x^2 -14x +49]
9 = y^2 -10y + x^2 -14x + 74
0 = x^2 + y^2 -14x -10y+ 74-9
0 = x^2 + y^2 -14x -10y+ 65
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