Question

Eliminate theta if x = 3 sec theta , y = 4 tan theta​

Answer 1

$x= 3sec A \\\\y =4 tan A$

$secA= \frac{x}{3}\\\\tanA=\frac{y}{4}$

By using identity:-

$sec^2A-tan^2A =1$

$(\frac{x}{3} )^2 - (\frac{y^2}{4})^2=1\\\\(\frac{x^{2}}{9}) - (\frac{y^{2} }{16})=1$

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