Eliminate theta if x=5 sec-3 tan theta.y=3sec theta+5 tan theta
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we know sec^2 t - tan ^2 t = 1 ( t for theta)
x = a * sec^3 t or sec^2 t = (x/a)^2/3
similarly tan ^2 t = (y/b)^2/3
so we get (x/a)^2/3 - (y/b)^2/3 = 1
HOPE IT WILL HELP YOU....
x = a * sec^3 t or sec^2 t = (x/a)^2/3
similarly tan ^2 t = (y/b)^2/3
so we get (x/a)^2/3 - (y/b)^2/3 = 1
HOPE IT WILL HELP YOU....
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