Question

eliminate theta, x=5+6cosec theta, y=3+8cot theta​

Answer 1

Answer:

The required equation is

$\frac{(x-5)^}{36}-\frac{(y-3)^2}{64}=1$

Step-by-step explanation:

$x=5+6\:cosec\theta$

$x-5=6\:cosec\theta$

$\implies\:cosec\theta=\frac{x-5}{6}=$

$y=3+8\:cot\theta$

​

$y-3=8\:cot\theta$

$\implies\:cot\theta=\frac{y-3}{8}$

Using

$\boxed{cosec^2\theta-cot^2\theta=1}$

$(\frac{x-5}{6})^2-(\frac{y-3}{8})^2=1$

$\implies\:\boxed{\frac{(x-5)^}{36}-\frac{(y-3)^2}{64}=1}$  which is the required equation

Answer 2

Step-by-step explanation:

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