Question

eliminating angle pfrom the equation x=asec^3p. y=btan^3p

Answer 1

Answer:

We know sec^2 t - tan ^2 t = 1 ( t for theta) 

x = a * sec^3 t or sec^2 t = (x/a)^2/3 

similarly tan ^2 t = (y/b)^2/3 

so we get (x/a)^2/3 - (y/b)^2/3 = 1


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