eliminating angle pfrom the equation x=asec^3p. y=btan^3p
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We know sec^2 t - tan ^2 t = 1 ( t for theta)
x = a * sec^3 t or sec^2 t = (x/a)^2/3
similarly tan ^2 t = (y/b)^2/3
so we get (x/a)^2/3 - (y/b)^2/3 = 1
I Hope It Will Help!
^_^
We know sec^2 t - tan ^2 t = 1 ( t for theta)
x = a * sec^3 t or sec^2 t = (x/a)^2/3
similarly tan ^2 t = (y/b)^2/3
so we get (x/a)^2/3 - (y/b)^2/3 = 1
I Hope It Will Help!
^_^
Needhelp0505:
then answer is the last step?
Yes, dear
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