elimination method
-10x-5y= -30
y+5x= 12
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2
Answer:
solution:
-10x-5y=-30. (1)
5x+y = 12. (2)
multiplying equation (2) by 5
25x+5y= 60. (3)
Adding equation (1) and (2)
-10x-5y= -30
25x+5y=60
15x =30
x = 30÷15
x = 2
and
putting the value of x in equation (2)
5 (2)+ y = 12
10+y = 12
y= 12-10
y= 2
Hence , x = 2 and y = 2
Answered by
1
-10x-5y= -30 _ (1)
y+5x= 12 _ (2)
using elimination method
-10x-5y = -30 _ (1)
10x+2y = 24 _(2) ×2
___________
3y. = 6. _ ( adding )
y = 6÷3
= 2
sub y in (2)
2 + 5x =12
5x = 10
x = 2
x = 2 , y = 2 is the solution
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