Question

elimination method 2x+2y=11 2x+3y=4​

Answer 1

Step-by-step explanation:

2x+2y=11. equation 1

2x+3y=4. equ 2

solve equ 1 and 2

2x+2y=11

2x+3y=4 (sign change + into -)

-y=7

y=-7

y=-7 in equ 1,we get

2x+2(-7)=11

2x-14=11

2x=25

x=25/2 .

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Answer 2

Given :

• 2x + 2y = 11
• 2x + 3y = 4

To Find :

• Value of x and y with elimination method.

Solution :

We have :

• 2x + 2y = 11 - (1)

• 2x + 3y = 4 -(2)

By eliminating 2x with help of subtraction of equation (2) from equation (1) :

$\sf \cancel{2x} + 2y = 11 \\ \sf\cancel{2x} + 3y = 4 \\ \bf - \: \: \: \: - \: \: \: \: \: - \\ \frac{\quad \: \quad \: \quad \: \quad \: \quad \: }{} \\ \sf - y = 7 \\ \frac{\quad \: \quad \: \quad \: \quad \: \quad \: }{}$

Therefore, we have :

$\Large \underline{\boxed{\bf{y = - 7}}}$

By putting value of y in equation (1) :

$\sf : \implies 2x + 2 (-7) = 11$

$\sf : \implies 2x - 14 = 11$

$\sf : \implies 2x = 11 + 14$

$\sf : \implies 2x = 25$

$\sf : \implies x = \dfrac{25}{2}$

$\sf : \implies x = 12.5$

$\Large \underline{\boxed{\bf{x = 12.5}}}$

Hence,

• $\Large \underline{\boxed{\bf{x = 12.5}}}$

• $\Large \underline{\boxed{\bf{y = - 7}}}$