elimination method 2x+5=5y+6 ,3(2x+y)=24-x
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2x + 5 = 5y + 6
2x - 5y = 6 - 5 = 1
2x - 5y = 1 ---------(1)
3(2x + y) = 24 -x
6x + 3y = 24 - x
7x + 3y = 24 ----------(2)
(1) × 7 =>
14x - 35y = 7 ---------(3)
(2) × 2 =>
14x + 6y = 48 ---------(4)
(4) - (3) =>
14x + 6y - 14x + 35y = 48 - 7
41y = 41
y = 41/41
y = 1
Substituting y = 1 in (1)
2x - 5y = 1
2x - 5(1) = 1
2x - 5 = 1
2x = 5 + 1
2x = 6
x = 3
Therefore,
x = 3 and
y = 1
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