Question

elimination method. 37x + 29y = 45 ;
29x + 37y = 21 ?
plz answer

Answer 1

first add both eqns
37x+29y=45
+
29x+37y=21
------------------
66x+66y=66
divide eqn by 6
so,x+y=1
then subtract eqns
37x+29y=45
_
29x+37y=21
------------------
8x-8y. =24
divide eqn by 8
so,x-y=3
again add both eqns which are obtained by addn n subn
so,
X+y=1
+
x-y=3
--------
2x=-2
so,x=-1
substitute x=-1
x-y=3
-1-y=3
y=3+1
y=4
so,x=-1&y=4
plz mark brainliest

Answer 2

HELLO DEAR,



GIVEN:- 37x + 29y = 45----------------( 1 )
29x + 37y = 21---------------( 2 )

adding--------( 1 ) & ----------( 2 )

37x + 29y = 45
29x + 37y = 21
----------------------
66x + 66y = 66

=> x + y = 1 -----------( 3 )


subtracting------( 1 ) From------( 2 )

29x + 37y = 21
37x + 29y = 45
----------------------
-8x + 8y = -24

=> y - x = -3
or, x - y = 3-------------( 4 )


now, from-----------( 3 ) & ------------( 4 )

x + y = 1
x - y = 3
--------------
2x = 4

=> x = 2 [ put in --- ( 3 )]

we get, x + y = 1

=> y = 1 - 2

=> y = -1

hence, x = 2 & y = -1



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