Question

elimination method linear equation in two variable

Answer 1

Here is your answer..>>>>>>>>>>

-5x+2y=6--(1)×3

3x-5y=4--(2)×5

-15x+6y=18

15x-25y=20

______________

-19y=38

y=38/-19


y=-2



Putting the value of y equation in (2)



3x-5y=4

=>3x-5×-2=4

=>3x-10=4

=>-10-4=3x

=>-6=3x

=>-6/3=x

=>-2=x

Answer 2

$-5x+2y=6-----(1) \\</p><p>3x-5y=4----(2) \\ \\ multiply \: equation \: (1) \: by \: 5 \\ multiply \: equation \: (2) \: by \: 2 \\ - 25x + 10y = 30 - - - - (3) \\ 6x - 10y = 8 - - - - - (4) \\ \\ add \: equation \: (3) \: and \: (4) \\ \\ - 25x + 10y = 30 \\ \frac{ + 6x - 10y = 8}{ - 19x \: \: \: \: \: \: \: \: \: \: = 38} \\ \\ x = \frac{38}{ - 19} \\ x = - 2 \\ \\ substitute \: x = - 2 \: in \: equation \: (2) \\ \\ 3( - 2) - 5y = 4 \\ ( - 6) - 5y = 4 \\ - 5y = 4 + 6 \\ - 5y = 10 \\ - y = \frac{10}{5} \\ - y = 2 \\ y = - 2$

solution is (x,y)=(-2,-2)

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