elimination method of 2x-3y=20 x-2y=13
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Answer:
⇒ 2x - 3y = 20 ... 1
⇒ x - 2y = 13 ... 2
Multiply eq 2 by 2 and subtract eq 2 from eq 1
we get, y = - 6
substitute in eq 1 we get, x = 1
⇒ (x, y) ≡ (1, -6)
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Step-by-step explanation:
2x-3y= 20 ------------ (i)
x-2y= 13 ------------ (ii)
Multiply equation (i) by 1 and equation (ii) by 2
2x-3y= 20 ----------- (iii)
2x-4y= 26 ----------- (iv)
Subtract eq.(iii) from (iv)
2x-4y= 26
2x-3y= 20
(+). (-)
------------------
-y= 6
y= -6
substitute the value of y in eq.(i)
2x-3y= 20
2x-3×(-6) = 20
2x+18= 20
2x= 20-18
2x= 2
x= 2/2
x= 1
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