Elimination method of 2x+y=35,3x+4y=65
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Answered by
3
Step-by-step explanation:
2x +y = 35........(1)
3x +4y = 65........(2)
Multiply (1) by 4=>
8x +4y = 140........(3)
Now solve (2)&(3)
(3)-(2)
8x +4y = 140
3x +4y = 65
- - -
_____________
5x = 75
x = 15
substitute x = 15 in (2)
3x +4y = 65
3(15) + 4y = 65
4y = 65-45
4y = 20
y = 5
So,
(x,y) = (15,5)
Answered by
0
Answer:
answer is
Step-by-step explanation:
2x+y=35,3x+4y=65
=2x+3x+4y+y=65-35
=5x+5y=30
=5(x+y)=30
=(x+y)=30/5
=(x+y)=6
therefore x+y=6
sorry bro Maine dhyan Nhi diya ki kis method me Karna hai.
plz mark the brilliant answer
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