Elimination method
X + Y = 3
4x - 3y = 26
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X+Y=3 .............(1)
4X-3Y=26...........(2)
Multiply eqn (1) by 3, we get,
3X+ 3Y= 9...........(3)
On adding eqn (3)&(2), we get,
(3X+4X) + (3Y-3Y) = 9+26
( 7X ) + 0 = 35
X= 35/7
{X= 5.}
On putting the value of X in eqn (1), we get,
5 + Y = 3
Y = 3- 5
{ Y = -2.}
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