Question

elimination of arbitary constant

Answer 1

ax² + by =1
or, ax²= 1- by
Differentiating both sides
2ax = - b dy/dx
or, - 2a/b = 1/x × dy/dx
Again differentiating both sides
0 = - 1/x² × dy/dx + 1/x × d²y/dx²
or, 1/x² × dy/dx = 1/x × d²y/dx²
or dy/dx = x × d²y/dx² ____(ans)
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