elimination question
3x+7y=2
6x-5y=4
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Answer:
x=2/3, y=0
Step-by-step explanation:
3x+7y=2--eq1
6x-5y=4--eq2
Multiple eq1 by 6 and eq2 by 3
6×(3x+7y=2)--›18x+42y=12--eq3
3×(6x-5y=4)--›18x-15y=12--eq4
Add eq3 and eq4, we get
57y=0
y=0/57
y=0
Substitute y=0 in eq1
3x+7y=2
3x+7(0)=2
3x+0=2
3x=2
x=2/3
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