Chemistry, asked by vijaydesai6098, 9 months ago

Elimination Reaction. ch3-ch2-chBr--ch3+koH​

Answers

Answered by Hemalathajothimani
3

Answer:

Explanation:

ANSWER

More the number of β- substituents (alkyl groups), more stable alkene it will form on β- elimination and more will be the reactivity. Hence, the decreasing order of the rate of β-elimination reaction with alcoholic KOH is →

2β−substituents

I

​  

>  

1β−substituents

III

​  

>  

0β−substituents

II

​  

.

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