Question

Elio makes candles that are 14\text{ cm}14 cm14, start text, space, c, m, end text tall. Each candle burns 888 hours before going out. He is wondering how many hours a 21\text{ cm}21 cm21, start text, space, c, m, end text tall candle can burn for.
He assumes that the relationship between the height of a candle and the number of hours it burns (h)(h)left parenthesis, h, right parenthesis is proportional.
How long a 21 \text{ cm}21 cm21, start text, space, c, m, end text tall candle can burn for?

Answer 1

Answer:

The answer is 12

Step-by-step explanation:

14/2 equal 7 and that is half of 14.

If you noticed 8/2 equals 4

4x3 = 12 and 7x3=21

Therefore the answer is 12

Answer 2

Answer:

The duration will be  1176 hours

Step-by-step explanation:

From the above question,

They have given :

Elio makes candles that are 14\text{ cm}14 cm14, start text, space, c, m, end text tall. Each candle burns 888 hours before going out. He is wondering how many hours a 21\text{ cm}21 cm21, start text, space, c, m, end text tall candle can burn for.

Using the formula h' = (h × h2)/h1

                              h' = ($\frac{h}{times }$ h_2) / h_1

                              h′ = (h×h2​)/h1​

where h1h_1h1​ is the height of the first candle 14 cm, start text, space, c, m, end text) and h2h_2h2​ is the height of the second candle 21 cm , start text, space, c, m, end text), the new number of hours a 21 \text{ cm}21 cm21, start text, space, c, m, end text tall candle can burn is:

h' = (888 × 21)/14

   = 1176 h'=( $\frac{888}{times}$ 21) / 14

   = 1176 h′

   = ( 888 × 21 ) / 14

  = 1176 hours

Hence,

       The duration will be  1176 hours

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