Math, asked by reema4890, 1 year ago

Eliza deposited ₹20,000in a bank at the rate of 10% per annum. Draw a linear graph showing the time and simple interest relationship. Also, find the simple interest for 4 years


poongothai110391: How to solve this problem ?

Answers

Answered by mysticd
5

 Eliza \: deposited \: the \: sum \: in \: a \:bank \\(P) = Rs \: 20000

 Rate \:of \: Interest (R) = 10\%\: per \: annum

 Time (T) = 1 \: year

 \boxed {\pink { I = \frac{PTR}{100} }}

 I = \frac{ 20000 \times 1 \: 10}{100} \\= Rs \:2000

 \begin {tabular} {|c|c|c| }</p><p>\cline {1-3} Time &amp; Simple Interest &amp; (T,I ) \\</p><p>\cline {1-3} 1&amp; 2000 &amp; (1,2000)\\</p><p>\cline {1-3} 2&amp;4000&amp;(2,4000)\\</p><p>\cline {1-3} 3&amp;6000&amp;(3,6000)\\</p><p>\cline {1-3} 4&amp;8000&amp;(4,8000)\\</p><p>\cline {1-3}\\</p><p>\end {tabular}

 \red {Relationship \: between \: Time (T) \: and \\Simple \: Interest :}

 \boxed {\ green { I = 2000 T }

 Simple \: Interest \: for \: 4\: years = 4 \times I \\= 4 \times 2000 \\= Rs \: 8000

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Answered by Anonymous
5

Given :

  • principle amount = 20000 Rs
  • rate = 10%
  • time = t

To find :

  • the simple interest for 4 years

Solution :

S. I. = (p x r x t)/100

= (20000 x 10 x t)/ 100

S.I = 2000 t .......... (1)

simple interest of per 4 years implies

t = 4

Put t = 4 in eq(1)

I = 2000 x 4

l = 8000

=> 8000Rs the simple interest for 4 years

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