Question

Ello guys!!❤


Differentiate the function...

cosx . cos2x . cos3x​

Answer 1

Answer:

dy/dx=-Cosx.Cos2x.Cos3x[tanx+2tan2x+3tan3x]

Step-by-step explanation:

we know....

d/dx (Cosx)= -Sinx

d/dx(Cos2x)=-sin2x(2)

.....

apply both the sides log will this sum make to solve easy...

Answer 2

hey prince...

here is your answer....

refer to the aatachment