Question

❤ Ello⭐Mates⭐

⏺When an object of height 1cm is kept at A distance 4cm from A concave mirror , its erect image of height 1.5cm is formed at A distance 6cm behind the mirror.
Find the focul length of mirror.

I need proper solution✔

No useless answers❎​

Answer 1

Answer:

Refer the attached picture.

Answer 2

Explanation:

$\Huge\underline{\underline{\sf ANSWER}}\\ height \: of \: object \: = h1 = 1cm \\ distance \: of \: object = u = - 4cm \\ u \: is \: always \: negetive...... \\ distance \: of \: image= v = 6 \\ \\ f = ? \\ \\ from \: lens \: formula = > \\ \frac{1}{v} + \frac{1}{u} = \frac{1}{f} \\ \frac{1}{6} - \frac{1}{4} = \frac{1}{f} \\ \frac{2 - 3}{12} = \frac{1}{f} \\ f = - 12 \: cm \\ - ve \: sign \: because \: focal \: length \: of \: concave \: is \: negetive \: always....$