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A 6.5 m long ladder is placed against a wall such that its foot is at a distance of 2.5 m from the wall. Find the height of the wall where the top of the ladder touches it?
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hellopankhuri1902:
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Answer:
In triangle ABC
by Pythagoras theorem
AC^2=AB^2+CB^2
CB^2=AC^2-AB^2
CB^2=(6.5)^2-(2.5)^2
=42.25-6.25
=36
CB=6
therefore the height of the wall is 6m.
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