★ELLOH,
\huge {\mathbb ♡{\orange{QUESTION}\green{♡}\pink{}\blue{!}}}♡♡QUESTION♡!♡
A 6.5 m long ladder is placed against a wall such that its foot is at a distance of 2.5 m from the wall. Find the height of the wall where the top of the ladder touches it?
★ REQUIRED QUALITY ANSWER
hellopankhuri1902:
kaha
acha haan
okk
byeee
who?
Answers
Answered by
2
Answer:
In triangle ABC
by Pythagoras theorem
AC^2=AB^2+CB^2
CB^2=AC^2-AB^2
CB^2=(6.5)^2-(2.5)^2
=42.25-6.25
=36
CB=6
therefore the height of the wall is 6m.
Hope it helps
Attachments:
Answered by
1
Hope it will help you!!
Attachments:
u haven't contacted me since that day..
also not from shreyash and afzal ji... we always talk about u that u r busy so u don't talk with us
hey
sakshi
if i put my old do may u remember me
ohk leave himanshu aap bhul gaye hai... mujhe..
aap shreyash 4697 se puchyega. byy
Similar questions