Question

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$\huge \mathfrak \orange{❥QUESTION}$


In the given figure, CD || LA and DE || AC. Find the length of CL if BE = 4 cm and EC = 2 cm.?

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Answer 1

Answer:

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Answer 2

Answer:

From the given figure, CD∥LA and DE∥AC,

Consider the △BCA,

BE/BC=BD/BA

By using the corollary of basic proportionality theorem,

BE/(BE+EC)=BD/AB

4/(4+2)=BD/AB … [equation (i)]

Then, consider the △BLA

BC/BL=BD/AB

By using the corollary of basic proportionality theorem,

6/(6+CL)=BD/AB … [equation (ii)]

Now, combining the equation (i) and equation (ii), we get

6/(6+CL)=4/6

By cross multiplication we get,

6×6=4×(6+CL)

24+4CL=36

4CL=36−24

CL=12/4

CL=3cm

Therefore, the length of CL is 3cm.