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If 2 sin square theta + 3 sin theta = zero find the permissible values of cos theta.
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2sin^2x + 3sinx = 0
So,
2sin^2x = - 3sinx
sinx = - 3/2 when x not equal to zero..... But sinx can not be less than - 1
So sinx = 0 is a possible solution for this equation
Which means x = 0, pi
So, cosx = 1 or - 1
Nishant Abhangi
JEE ADVANCED 2019, AIR 6
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